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[8/29] 200. Number of Islands

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작성일 2022.08.28 17:34

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200. Number of Islands

Medium

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Given an m x n 2D binary grid grid which represents a map of '1's (land) and '0's (water), return the number of islands.

An island is surrounded by water and is formed by connecting adjacent lands horizontally or vertically. You may assume all four edges of the grid are all surrounded by water.

Example 1:

Input: grid = [
  ["1","1","1","1","0"],
  ["1","1","0","1","0"],
  ["1","1","0","0","0"],
  ["0","0","0","0","0"]
]
Output: 1

Example 2:

Input: grid = [
  ["1","1","0","0","0"],
  ["1","1","0","0","0"],
  ["0","0","1","0","0"],
  ["0","0","0","1","1"]
]
Output: 3

Constraints:

m == grid.length
n == grid[i].length
1 <= m, n <= 300
grid[i][j] is '0' or '1'.

Accepted

1,771,851

Submissions

3,206,958

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링크

https://leetcode.com/problems/number-of-islands/ 2742 회 연결

익명
작성일 2022.08.28 17:34

Runtime: 517 ms, faster than 43.44% of Python3 online submissions for Number of Islands.
Memory Usage: 25.1 MB, less than 12.15% of Python3 online submissions for Number of Islands.

class Solution:
    def numIslands(self, grid: List[List[str]]) -> int:
        island_count = 0
        
        visited = set()
        
        ROW, COL = len(grid), len(grid[0])
        directions = [[1,0],[0,1],[-1,0],[0,-1]]
        
        
        def dfs(row, col):
            if row >= ROW or col >= COL or row < 0 or col < 0 or (row,col) in visited or grid[row][col] == "0":
                return
            
            visited.add((row,col))
            
            for row_dir, col_dir in directions:
                dfs(row + row_dir, col + col_dir)
            
        
        for i in range(ROW):
            for j in range(COL):
                if (i,j) not in visited and grid[i][j] == "1":
                    dfs(i,j)
                    island_count += 1
        
        return island_count

Runtime: 517 ms, faster than 43.44% of Python3 online submissions for Number of Islands.
Memory Usage: 25.1 MB, less than 12.15% of Python3 online submissions for Number of Islands.
[code=Python 3]class Solution:
    def numIslands(self, grid: List[List[str]]) -> int:
        island_count = 0
        
        visited = set()
        
        ROW, COL = len(grid), len(grid[0])
        directions = [[1,0],[0,1],[-1,0],[0,-1]]
        
        
        def dfs(row, col):
            if row >= ROW or col >= COL or row < 0 or col < 0 or (row,col) in visited or grid[row][col] == "0":
                return
            
            visited.add((row,col))
            
            for row_dir, col_dir in directions:
                dfs(row + row_dir, col + col_dir)
            
        
        for i in range(ROW):
            for j in range(COL):
                if (i,j) not in visited and grid[i][j] == "1":
                    dfs(i,j)
                    island_count += 1
        
        return island_count[/code]