LeetCode 솔루션 분류
[10/29] 2136. Earliest Possible Day of Full Bloom
본문
Hard
113163Add to ListShareYou have n
flower seeds. Every seed must be planted first before it can begin to grow, then bloom. Planting a seed takes time and so does the growth of a seed. You are given two 0-indexed integer arrays plantTime
and growTime
, of length n
each:
plantTime[i]
is the number of full days it takes you to plant theith
seed. Every day, you can work on planting exactly one seed. You do not have to work on planting the same seed on consecutive days, but the planting of a seed is not complete until you have workedplantTime[i]
days on planting it in total.growTime[i]
is the number of full days it takes theith
seed to grow after being completely planted. After the last day of its growth, the flower blooms and stays bloomed forever.
From the beginning of day 0
, you can plant the seeds in any order.
Return the earliest possible day where all seeds are blooming.
Example 1:
Input: plantTime = [1,4,3], growTime = [2,3,1] Output: 9 Explanation: The grayed out pots represent planting days, colored pots represent growing days, and the flower represents the day it blooms. One optimal way is: On day 0, plant the 0th seed. The seed grows for 2 full days and blooms on day 3. On days 1, 2, 3, and 4, plant the 1st seed. The seed grows for 3 full days and blooms on day 8. On days 5, 6, and 7, plant the 2nd seed. The seed grows for 1 full day and blooms on day 9. Thus, on day 9, all the seeds are blooming.
Example 2:
Input: plantTime = [1,2,3,2], growTime = [2,1,2,1] Output: 9 Explanation: The grayed out pots represent planting days, colored pots represent growing days, and the flower represents the day it blooms. One optimal way is: On day 1, plant the 0th seed. The seed grows for 2 full days and blooms on day 4. On days 0 and 3, plant the 1st seed. The seed grows for 1 full day and blooms on day 5. On days 2, 4, and 5, plant the 2nd seed. The seed grows for 2 full days and blooms on day 8. On days 6 and 7, plant the 3rd seed. The seed grows for 1 full day and blooms on day 9. Thus, on day 9, all the seeds are blooming.
Example 3:
Input: plantTime = [1], growTime = [1] Output: 2 Explanation: On day 0, plant the 0th seed. The seed grows for 1 full day and blooms on day 2. Thus, on day 2, all the seeds are blooming.
Constraints:
n == plantTime.length == growTime.length
1 <= n <= 105
1 <= plantTime[i], growTime[i] <= 104
Accepted
36,351
Submissions
48,401
태그
#Visa
관련자료
-
링크
댓글 1
학부유학생님의 댓글
- 익명
- 작성일
https://leetcode.com/problems/earliest-possible-day-of-full-bloom/discuss/1676837/Grow-then-plant
Runtime: 4627 ms, faster than 16.45% of Python3 online submissions for Earliest Possible Day of Full Bloom.
Memory Usage: 30.9 MB, less than 90.65% of Python3 online submissions for Earliest Possible Day of Full Bloom.
Runtime: 4627 ms, faster than 16.45% of Python3 online submissions for Earliest Possible Day of Full Bloom.
Memory Usage: 30.9 MB, less than 90.65% of Python3 online submissions for Earliest Possible Day of Full Bloom.
class Solution:
def earliestFullBloom(self, plantTime: List[int], growTime: List[int]) -> int:
res = 0
for gt, pt in sorted(zip(growTime, plantTime)):
res = max(res, gt) + pt
return res