엔지니어 게시판
LeetCode 솔루션 분류

[8/8] 300. Longest Increasing Subsequence

컨텐츠 정보

본문

Medium
13979256Add to ListShare

Given an integer array nums, return the length of the longest strictly increasing subsequence.

subsequence is a sequence that can be derived from an array by deleting some or no elements without changing the order of the remaining elements. For example, [3,6,2,7] is a subsequence of the array [0,3,1,6,2,2,7].

 

Example 1:

Input: nums = [10,9,2,5,3,7,101,18]
Output: 4
Explanation: The longest increasing subsequence is [2,3,7,101], therefore the length is 4.

Example 2:

Input: nums = [0,1,0,3,2,3]
Output: 4

Example 3:

Input: nums = [7,7,7,7,7,7,7]
Output: 1

 

Constraints:

  • 1 <= nums.length <= 2500
  • -104 <= nums[i] <= 104

 

Follow up: Can you come up with an algorithm that runs in O(n log(n)) time complexity?

Accepted
976,302
Submissions
1,924,672

관련자료

댓글 1

학부유학생님의 댓글

  • 익명
  • 작성일
class Solution:
    def lengthOfLIS(self, nums: List[int]) -> int:
        dp = [1]*len(nums)
        
        for i in range(len(nums)-1, -1, -1):
            max_lis = 0
            for j in range(i+1, len(nums)):
                if nums[i] < nums[j]:
                    max_lis = max(dp[j], max_lis)
            dp[i] = max_lis + 1
        
        return max(dp)
전체 405 / 1 페이지
번호
제목
이름

최근글


인기글


새댓글


Stats


  • 현재 접속자 583 명
  • 오늘 방문자 3,248 명
  • 어제 방문자 7,414 명
  • 최대 방문자 14,831 명
  • 전체 회원수 1,543 명
알림 0