LeetCode 솔루션 분류
[8/30] 48. Rotate Image
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Medium
11082548Add to ListShareYou are given an n x n 2D matrix representing an image, rotate the image by 90 degrees (clockwise).
You have to rotate the image in-place, which means you have to modify the input 2D matrix directly. DO NOT allocate another 2D matrix and do the rotation.
Example 1:
Input: matrix = [[1,2,3],[4,5,6],[7,8,9]] Output: [[7,4,1],[8,5,2],[9,6,3]]
Example 2:
Input: matrix = [[5,1,9,11],[2,4,8,10],[13,3,6,7],[15,14,12,16]] Output: [[15,13,2,5],[14,3,4,1],[12,6,8,9],[16,7,10,11]]
Constraints:
n == matrix.length == matrix[i].length1 <= n <= 20-1000 <= matrix[i][j] <= 1000
Accepted
1,015,099
Submissions
1,482,894
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Runtime: 38 ms, faster than 91.36% of Python3 online submissions for Rotate Image.
Memory Usage: 13.8 MB, less than 74.32% of Python3 online submissions for Rotate Image.
Memory Usage: 13.8 MB, less than 74.32% of Python3 online submissions for Rotate Image.
class Solution:
def rotate(self, matrix: List[List[int]]) -> None:
"""
Do not return anything, modify matrix in-place instead.
"""
top, bottom = 0, len(matrix)-1
left, right = 0, len(matrix[0])-1
while left < right or top < bottom:
for i in range(right - left):
# tl->tr
temp_rt = matrix[top+i][right]
matrix[top+i][right] = matrix[top][left+i]
# rt->rb
temp_rb = matrix[bottom][right-i]
matrix[bottom][right-i] = temp_rt
#rb->lb
temp_lb = matrix[bottom-i][left]
matrix[bottom-i][left] = temp_rb
#lb->tl
matrix[top][left+i] = temp_lb
left +=1
right -=1
top+=1
bottom-=1
return matrix
