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[12/13] 931. Minimum Falling Path Sum

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작성일 2022.12.13 14:28

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931. Minimum Falling Path Sum

Given an n x n array of integers matrix, return the minimum sum of any falling path through matrix.

A falling path starts at any element in the first row and chooses the element in the next row that is either directly below or diagonally left/right. Specifically, the next element from position (row, col) will be (row + 1, col - 1), (row + 1, col), or (row + 1, col + 1).

Example 1:

Input: matrix = [[2,1,3],[6,5,4],[7,8,9]]
Output: 13
Explanation: There are two falling paths with a minimum sum as shown.

Example 2:

Input: matrix = [[-19,57],[-40,-5]]
Output: -59
Explanation: The falling path with a minimum sum is shown.

Constraints:

n == matrix.length == matrix[i].length
1 <= n <= 100
-100 <= matrix[i][j] <= 100

Accepted

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Submissions

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링크

https://leetcode.com/problems/minimum-falling-path-sum/description/ 887 회 연결

익명
작성일 2022.12.13 14:29

class Solution:
    def minFallingPathSum(self, matrix: List[List[int]]) -> int:
        dic = {}
        
        ROW, COL = len(matrix), len(matrix[0])
        directions = [(1,-1),(1,1),(1,0)]

        def dfs(r, c):
            if r == ROW-1:
                return matrix[r][c]
            if (r,c) in dic: return dic[(r,c)]
            

            min_path = float('inf')

            for rd, cd in directions:
                nr, nc = r + rd, c+cd
                if 0<=nr<ROW and 0<=nc<COL:
                    min_path = min(min_path, dfs(nr,nc))
            
            dic[(r,c)] = min_path + matrix[r][c]

            return min_path + matrix[r][c]


        return min(dfs(0,c) for c in range(COL))