LeetCode 솔루션

[1/7] 134. Gas Station

학부유학생 쪽지보내기 메일보내기 자기소개 아이디로 검색 전체게시물 작성
작성일 2023.01.07 12:56

5,469 조회
1 댓글
0 추천
0 비추천
목록 게시글 쓰기

There are n gas stations along a circular route, where the amount of gas at the ith station is gas[i].

You have a car with an unlimited gas tank and it costs cost[i] of gas to travel from the ith station to its next (i + 1)th station. You begin the journey with an empty tank at one of the gas stations.

Given two integer arrays gas and cost, return the starting gas station's index if you can travel around the circuit once in the clockwise direction, otherwise return -1. If there exists a solution, it is guaranteed to be unique

Example 1:

Input: gas = [1,2,3,4,5], cost = [3,4,5,1,2]
Output: 3
Explanation:
Start at station 3 (index 3) and fill up with 4 unit of gas. Your tank = 0 + 4 = 4
Travel to station 4. Your tank = 4 - 1 + 5 = 8
Travel to station 0. Your tank = 8 - 2 + 1 = 7
Travel to station 1. Your tank = 7 - 3 + 2 = 6
Travel to station 2. Your tank = 6 - 4 + 3 = 5
Travel to station 3. The cost is 5. Your gas is just enough to travel back to station 3.
Therefore, return 3 as the starting index.

Example 2:

Input: gas = [2,3,4], cost = [3,4,3]
Output: -1
Explanation:
You can't start at station 0 or 1, as there is not enough gas to travel to the next station.
Let's start at station 2 and fill up with 4 unit of gas. Your tank = 0 + 4 = 4
Travel to station 0. Your tank = 4 - 3 + 2 = 3
Travel to station 1. Your tank = 3 - 3 + 3 = 3
You cannot travel back to station 2, as it requires 4 unit of gas but you only have 3.
Therefore, you can't travel around the circuit once no matter where you start.

Constraints:

n == gas.length == cost.length
1 <= n <= 105
0 <= gas[i], cost[i] <= 104

Accepted

544.3K

Submissions

<div class="text-label-1 dark:text-dark-label-1 text-sm font-medium" style="border: 0px solid; box-sizing: border-box; --tw-border-spacing-x:0; --tw-border-spacing-y:0; --tw-translate-x:0; --tw-translate-y:0; --tw-rotate:0; --tw-skew-x:0; --tw-skew-y:0; --tw-scale-x:1; --tw-scale-y:1; --tw-pan-x: ; --tw-pan-y: ; --tw-pinch-zoom: ; --tw-scroll-snap-strictness:proximit

#Amazon, #Bloomberg, #Microsoft, #Walmart Global Tech, #PhonePe

링크

https://leetcode.com/problems/gas-station/ 745 회 연결

익명
작성일 2023.01.07 12:56

class Solution:
    def canCompleteCircuit(self, gas: List[int], cost: List[int]) -> int:
        diff = [gas[i]-cost[i] for i in range(len(gas))]

        if sum(diff)<0: return -1

        partsum = 0
        start = 0

        for i in range(len(diff)):
            partsum += diff[i]
            if partsum <0:
                start = i + 1
                partsum = 0
        
        return start