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[9/23] 1680. Concatenation of Consecutive Binary Numbers
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Medium
996364Add to ListShareGiven an integer n, return the decimal value of the binary string formed by concatenating the binary representations of 1 to n in order, modulo 109 + 7.
Example 1:
Input: n = 1 Output: 1 Explanation: "1" in binary corresponds to the decimal value 1.
Example 2:
Input: n = 3 Output: 27 Explanation: In binary, 1, 2, and 3 corresponds to "1", "10", and "11". After concatenating them, we have "11011", which corresponds to the decimal value 27.
Example 3:
Input: n = 12 Output: 505379714 Explanation: The concatenation results in "1101110010111011110001001101010111100". The decimal value of that is 118505380540. After modulo 109 + 7, the result is 505379714.
Constraints:
1 <= n <= 105
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Submissions
117,539
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class Solution:
def concatenatedBinary(self, n: int) -> int:
num = ""
for i in range(1,n+1):
num+=format(i,"b")
return int(num,2)%(10**9 + 7)
