LeetCode 솔루션

[11/23] 36. Valid Sudoku

학부유학생 쪽지보내기 메일보내기 자기소개 아이디로 검색 전체게시물 작성
작성일 2022.11.23 11:58

5,880 조회
1 댓글
0 추천
0 비추천
목록

글검색

게시글 쓰기

Medium

7416836Add to ListShare

Determine if a 9 x 9 Sudoku board is valid. Only the filled cells need to be validated according to the following rules:

Each row must contain the digits 1-9 without repetition.
Each column must contain the digits 1-9 without repetition.
Each of the nine 3 x 3 sub-boxes of the grid must contain the digits 1-9 without repetition.

Note:

A Sudoku board (partially filled) could be valid but is not necessarily solvable.
Only the filled cells need to be validated according to the mentioned rules.

Example 1:

Input: board = 
[["5","3",".",".","7",".",".",".","."]
,["6",".",".","1","9","5",".",".","."]
,[".","9","8",".",".",".",".","6","."]
,["8",".",".",".","6",".",".",".","3"]
,["4",".",".","8",".","3",".",".","1"]
,["7",".",".",".","2",".",".",".","6"]
,[".","6",".",".",".",".","2","8","."]
,[".",".",".","4","1","9",".",".","5"]
,[".",".",".",".","8",".",".","7","9"]]
Output: true

Example 2:

Input: board = 
[["8","3",".",".","7",".",".",".","."]
,["6",".",".","1","9","5",".",".","."]
,[".","9","8",".",".",".",".","6","."]
,["8",".",".",".","6",".",".",".","3"]
,["4",".",".","8",".","3",".",".","1"]
,["7",".",".",".","2",".",".",".","6"]
,[".","6",".",".",".",".","2","8","."]
,[".",".",".","4","1","9",".",".","5"]
,[".",".",".",".","8",".",".","7","9"]]
Output: false
Explanation: Same as Example 1, except with the 5 in the top left corner being modified to 8. Since there are two 8's in the top left 3x3 sub-box, it is invalid.

Constraints:

board.length == 9
board[i].length == 9
board[i][j] is a digit 1-9 or '.'.

Accepted

961,603

Submissions

1,669,639

#Amazon, #Apple, #Karat, #Uber, #Adobe, #Bloomberg, #Tesla, #Nvidia, #Jump Trading

링크

https://leetcode.com/problems/valid-sudoku/ 970 회 연결

익명
작성일 2022.11.23 11:58

class Solution:
    def isValidSudoku(self, board: List[List[str]]) -> bool:
        ROW, COL = len(board), len(board[0])
        
        # check each col
        for r in range(ROW):
            check = [0]*10
            for c in range(COL):
                if board[r][c].isdigit():
                    if check[int(board[r][c])]: return False
                    check[int(board[r][c])] += 1
        
        # check each row
        for c in range(COL):
            check = [0]*10
            for r in range(ROW):
                if board[r][c].isdigit():
                    if check[int(board[r][c])]: return False
                    check[int(board[r][c])] += 1
        
        
        for row in range(3):
            for col in range(3):
                start_r = row*3
                start_c = col*3
                
                check = [0]*10
                for r in range(start_r, start_r+3):
                    for c in range(start_c, start_c+3):
                        if board[r][c].isdigit():
                            if check[int(board[r][c])]: return False
                            check[int(board[r][c])] += 1
        
        return True

[code=Python 3]class Solution:
    def isValidSudoku(self, board: List[List[str]]) -> bool:
        ROW, COL = len(board), len(board[0])
        
        # check each col
        for r in range(ROW):
            check = [0]*10
            for c in range(COL):
                if board[r][c].isdigit():
                    if check[int(board[r][c])]: return False
                    check[int(board[r][c])] += 1
        
        # check each row
        for c in range(COL):
            check = [0]*10
            for r in range(ROW):
                if board[r][c].isdigit():
                    if check[int(board[r][c])]: return False
                    check[int(board[r][c])] += 1
        
        
        for row in range(3):
            for col in range(3):
                start_r = row*3
                start_c = col*3
                
                check = [0]*10
                for r in range(start_r, start_r+3):
                    for c in range(start_c, start_c+3):
                        if board[r][c].isdigit():
                            if check[int(board[r][c])]: return False
                            check[int(board[r][c])] += 1
        
        return True[/code]