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[12/4] 2256. Minimum Average Difference

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작성일 2022.12.04 14:04

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You are given a 0-indexed integer array nums of length n.

The average difference of the index i is the absolute difference between the average of the first i + 1 elements of nums and the average of the last n - i - 1 elements. Both averages should be rounded down to the nearest integer.

Return the index with the minimum average difference. If there are multiple such indices, return the smallest one.

Note:

The absolute difference of two numbers is the absolute value of their difference.
The average of n elements is the sum of the n elements divided (integer division) by n.
The average of 0 elements is considered to be 0.

Example 1:

Input: nums = [2,5,3,9,5,3]
Output: 3
Explanation:
- The average difference of index 0 is: |2 / 1 - (5 + 3 + 9 + 5 + 3) / 5| = |2 / 1 - 25 / 5| = |2 - 5| = 3.
- The average difference of index 1 is: |(2 + 5) / 2 - (3 + 9 + 5 + 3) / 4| = |7 / 2 - 20 / 4| = |3 - 5| = 2.
- The average difference of index 2 is: |(2 + 5 + 3) / 3 - (9 + 5 + 3) / 3| = |10 / 3 - 17 / 3| = |3 - 5| = 2.
- The average difference of index 3 is: |(2 + 5 + 3 + 9) / 4 - (5 + 3) / 2| = |19 / 4 - 8 / 2| = |4 - 4| = 0.
- The average difference of index 4 is: |(2 + 5 + 3 + 9 + 5) / 5 - 3 / 1| = |24 / 5 - 3 / 1| = |4 - 3| = 1.
- The average difference of index 5 is: |(2 + 5 + 3 + 9 + 5 + 3) / 6 - 0| = |27 / 6 - 0| = |4 - 0| = 4.
The average difference of index 3 is the minimum average difference so return 3.

Example 2:

Input: nums = [0]
Output: 0
Explanation:
The only index is 0 so return 0.
The average difference of index 0 is: |0 / 1 - 0| = |0 - 0| = 0.

Constraints:

1 <= nums.length <= 105
0 <= nums[i] <= 105

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링크

https://leetcode.com/problems/minimum-average-difference/ 939 회 연결

익명
작성일 2022.12.04 14:04

Runtime: 2905 ms, faster than 22.80% of Python3 online submissions for Minimum Average Difference.
Memory Usage: 25.6 MB, less than 30.55% of Python3 online submissions for Minimum Average Difference.

class Solution:
    def minimumAverageDifference(self, nums: List[int]) -> int:
        preSum = [nums[0]]
        for i in range(1, len(nums)):
            preSum.append(preSum[i-1] + nums[i])
        
        min_diff = float('inf')
        min_idx = 0
        
        for i in range(len(preSum)):
            diff = abs(preSum[i]//(i+1) - (preSum[-1] - preSum[i])//max(len(preSum)-1 -i,1 ) )
            
            if diff < min_diff:
                min_diff = diff
                min_idx = i
            
    
        return min_idx