엔지니어 게시판
LeetCode 솔루션 분류

[12/16] 232. Implement Queue using Stacks

컨텐츠 정보

본문

Implement a first in first out (FIFO) queue using only two stacks. The implemented queue should support all the functions of a normal queue (pushpeekpop, and empty).

Implement the MyQueue class:

  • void push(int x) Pushes element x to the back of the queue.
  • int pop() Removes the element from the front of the queue and returns it.
  • int peek() Returns the element at the front of the queue.
  • boolean empty() Returns true if the queue is empty, false otherwise.

Notes:

  • You must use only standard operations of a stack, which means only push to toppeek/pop from topsize, and is empty operations are valid.
  • Depending on your language, the stack may not be supported natively. You may simulate a stack using a list or deque (double-ended queue) as long as you use only a stack's standard operations.

 

Example 1:

Input
["MyQueue", "push", "push", "peek", "pop", "empty"]
[[], [1], [2], [], [], []]
Output
[null, null, null, 1, 1, false]

Explanation
MyQueue myQueue = new MyQueue();
myQueue.push(1); // queue is: [1]
myQueue.push(2); // queue is: [1, 2] (leftmost is front of the queue)
myQueue.peek(); // return 1
myQueue.pop(); // return 1, queue is [2]
myQueue.empty(); // return false

 

<span style="border: 0px solid; box-sizing: border-box; --tw-border-spacing-x:0; --tw-border-spacing-y:0; --tw-translate-x:0; --tw-translate-y:0; --tw-rotate:0; --tw-skew-x:0; --tw-skew-y:0; --tw-scale-x:1; --tw-scale-y:1; --tw-pan-x: ; --tw-pan-y: ; --tw-pinch-zoom: ; --tw-scroll-snap-strictn

태그

관련자료

댓글 1

학부유학생님의 댓글

  • 익명
  • 작성일
class MyQueue:

    def __init__(self):
        self.stack1 = []
        self.stack2 = []

    def push(self, x: int) -> None:
        self.stack1.append(x)

    def pop(self) -> int:
        if not self.stack2:
            self.move()
        return self.stack2.pop()

    def peek(self) -> int:
        if not self.stack2:
            self.move()
        return self.stack2[-1]

    def empty(self) -> bool:
        return not self.stack1 and not self.stack2

    def move(self):
        while self.stack1:
            self.stack2.append(self.stack1.pop())

        


# Your MyQueue object will be instantiated and called as such:
# obj = MyQueue()
# obj.push(x)
# param_2 = obj.pop()
# param_3 = obj.peek()
# param_4 = obj.empty()
전체 404 / 1 페이지
번호
제목
이름

최근글


인기글


새댓글


Stats


  • 현재 접속자 785 명
  • 오늘 방문자 7,080 명
  • 어제 방문자 7,907 명
  • 최대 방문자 14,831 명
  • 전체 회원수 1,525 명
알림 0